How do I eject a person from my Zoom class meeting?
If you need to eject someone from a Zoom class meeting, there are two ways to go about it.
If you wish to temporarily remove the person, knowing that you might re-admit them later, you can place them in a waiting room temporarily.
Or you can permanently eject a person from the meeting without the possibility of re-entry.
Method 1 - Place someone temporarily in the waiting room
NOTE: in order to use this option the waiting room must be enabled in the Zoom meeting. You can enable it either before the class meeting starts, or during the meeting. To enable the waiting room before starting the meeting, see: How do I enable the waiting room in Zoom?
If the waiting room is not yet enabled, click the Security icon in the Zoom toolbar and choose "Enable Waiting Room"
Once the waiting room is enabled, open the Participants window by clicking "Participants" in the Zoom toolbar
In the Participants window, find the person, click "More" next to their name, and choose "Put in Waiting Room"
NOTE: When a person is in the waiting room they can't communicate with you or other meeting participants. So if you wish to communicate with that person while they're in the waiting room, you would have to contact them a different way.
Method 2 - Eject someone from a meeting permanently
Open the Participants window by clicking "Participants" in the Zoom toolbar
In the Participants window, find the person, click "More" next to their name, and choose "Remove"
Leave the "Report to Zoom" box checked, to notify Zoom that you have removed a disruptive participant from your meeting.
NOTE: if you cannot quickly find the person's name in the participants window, you can choose "Suspend Participant Activities" from the Security menu. This will temporarily turn off all participant's video, audio, and sharing of participants. You can then turn on your video and audio, explain the situation, and ask participants to stand by while you take care of it.
To learn more see: How do I pause the entire Zoom meeting if there's a problem?